$\int2\left(3x^2+2x-5\right)^6\left(3x+1\right)dx$

$ln\left(\frac{8}{\sqrt{x^3+5}}\right)$

$\int7x\cdot sen\left(4x+3\right)dx$

$\frac{sec}{cos}-tan^2x=1$

$\int\left(\frac{x}{\sqrt{3x^2+4}}\right)dx$

$\left(x^3-4x\right)\left(8-2x^2\right)$

$\sec\left(x\right)-\cos\left(x\right)=\frac{\left(\tan\left(x\right)\right)^2}{\sec\left(x\right)}$