$\frac{dy}{dx}\left(y=9e^{\left(ln\left(2x\right)\right)^8}\right)$

$\frac{5x^4-4x^3+6x-3}{x+2}$

$\lim_{x,y\to0,0}\left(\frac{xy}{x}\right)$

$-\frac{3}{5}x+2>-1$

$\:\int\tan\left(\frac{5}{6}x\right)dx$

$9x-9-8x-32$

$\lim_{y\to1}\left(\frac{y^2-2y+1}{y^3-4y+3}\right)$