$4x^2-121$
$\frac{dy}{dx}\left(y=\left(8x\right)^x\right)$
$\left(4x+8\right)\left(2x+4\right)$
$\frac{4}{s^3+4s}$
$y\text{4}-xy\text{2}+y\text{3}$
$y'=y+8$
$4x\:+\:5=3x+20$
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