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- Integrate by partial fractions
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- Product of Binomials with Common Term
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Rewrite the integrand $t^2\left(t+\frac{-8}{t}\right)$ in expanded form
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$\int\left(t^{3}-8t\right)dt$
Learn how to solve problems step by step online. Find the integral int(t^2(t+-8/t))dt. Rewrite the integrand t^2\left(t+\frac{-8}{t}\right) in expanded form. Expand the integral \int\left(t^{3}-8t\right)dt into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int t^{3}dt results in: \frac{t^{4}}{4}. The integral \int-8tdt results in: -4t^2.