$-8p+10\left(1-x\right)$
$x^3-5x^2+2x+3-2x^3+5x^2-2x-3$
$1x^2+4x$
$1-2x\le0$
$\frac{\left(2s^2+4s-47\right)}{\left(s-4\right)\left(s+6\right)}$
$8a^2b^2+4ab-12$
$\sqrt{ax^3}$
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