$05a+05b^2$
$\int\:\left(\tan4y^2\right)ydy$
$\frac{5x^2-6x+4}{x+1}$
$\frac{\left(-3\right).\left(+8\right)+\left(-5\right).\left(+3\right)}{\left(13\right)}$
$\frac{0,2+1.1}{0.6}-1$
$130-96+210-100$
$3x-4\le6$
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