$\frac{\left(a^4-6a^3+2a^2+3a-4\right)}{\left(a^2-a+2\right)}$
$\frac{5}{6}\cdot30$
$\frac { 2 + 2 } { 4 }$
$6-8m+2m$
$14m=-196$
$\left(6x^n+2a^m\right)\left(6x^n-2a^m\right)$
$\left(2x+f-j\right)^2$
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