$\left(\frac{4x-5}{3}\right)=\left(\frac{3x-7}{2}\right)$
$3xy^2+2a-4-3xy^2+a-5+2a-xy^2$
$-5x\:-\:3y\:-\:6z\:+\:-5x\:-\:3y\:-\:6z$
$h^2-\frac{3}{4}h$
$\frac{dy}{dx}\left(12x^4y^2-7xy^3=4-8y\right)$
$-598\:-\:\left(-6\right)$
$\int\left(\frac{sec^2\left(x\right)}{tan^3\left(x\right)}\right)dx$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!