$\frac{2x^3+x-3}{x-3}\:$
$\frac{\sin\left(4x\right)}{\sin\left(2x\right)}\cdot\sin\left(2x\right)$
$-5\:+\:5\:-\:9\:+\:6\:+\:\left[-7\:-\:\left(-2\right)\right]\:+\:7\:-\:2$
$2x^2-7x+4=0$
$x+25=2$
$\frac{1}{sec\left(x+1\right)}+\frac{1}{sec\left(x-1\right)}$
$x=\sqrt{x^2-10x+25}$
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