$-2\:x\:\left(-3\right)^3$
$2x^2+10x-48=0$
$\left(\frac{1}{17}\right)^{-4}$
$\int x\left(x-7\right)^{\frac{1}{3}}dx$
$1-\sin\left(x\right)+\sin^4\left(x\right)=\cos^4\left(x\right)$
$9x-x$
$-13-29+34+-96$
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