$a+2a+3a-6a$
$3\:\tan^2\left(x\right)+1=0$
$3\left(17-19\right)$
$-4\cdot9-7$
$\frac{14x^2\:+22x-12}{7x\:-3}$
$0-\left(-28\right)$
$\int\left(3x^2-5\right)^7dx$
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