$x^2-14x+58=0$
$4y^3\left(\frac{dy}{dx}\right)=3sqrt\left(x\right)$
$3x^2-6y^2-7x-40y^2+9y^2+16^2$
$\frac{1}{secx+tanx}+\frac{1}{cotx}$
$-6^2+7x-5$
$\frac{dy}{dx}=\left(y-5\right)\left(y+5\right)$
$\left(5\right)\left(-4\right)-15$
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