$\left(x_{-3}^2\right)^2=\frac{x}{4}$
$log\left(-1.5\right)$
$\lim_{x\to\infty}e^x\left(\tan\left(-\frac{1}{x}\right)-\frac{\pi}{2}\right)$
$26-32+\left(-13\right)+\left|-6\right|$
$\frac{3}{x}=1+\frac{x-13}{6}$
$\frac{d}{dx}-9x^{\frac{2}{3}}+12-5x^{-8}+4x$
$3x^2+x-2$
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