$1+0-24+0-25$
$16x^3yz^2\:and\:24x^2yz^4$
$\left(1+\cos^2\left(x\right)\right)\left(1-\cos\left(2x\right)\right)$
$\int\frac{14y-4}{\left(7y^2-4y\right)^3}dy$
$\lim_{x\to-2}\left(\frac{x^2-5x+6}{x-2}\right)$
$-\left(-5\right)^2+6\left(-5\right)$
$x^2-8=28$
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