$\left(5x^5-by\right)^2$
$a^24a+3$
$\lim_{x\to-1}\left(\frac{\left(8x^4+7x^3+6x+5\right)}{x+1}\right)$
$\frac{6}{1-x^3}$
$x+10>2$
$2x\left(-n-3\right)-7\left(5+2n\right)$
$\frac{x^3-6}{x^4+6x^2+8}$
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