$3x-8\ge2x+9$
$\frac{8x^3+27m^3n^6}{2x+3mn^2}$
$5x-\:4y\:-3y$
$64^{x+2}=32^{x+4}$
$\frac{\tan\left(x+y\right)-\tan\left(x\right)}{1+\tan\left(x+y\right)\tan\left(x\right)}$
$-4+8\left(27-35\right)-60$
$\frac{1}{2}\left(150\right)\left(15\right)^2$
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