$\int_0^3\left(\frac{x-1}{x^2-3x-4}\right)dx$
$\lim_{x\to\infty}\left(\frac{x+\cos\left(x\right)}{x-\cos\left(x\right)}\right)$
$1x^2-8x+17$
$4u-24$
$4x^2+36xy$
$-6x-2+4x-9$
$\frac{1-\cos\left(x\right)^4-\sin\left(x\right)^2}{\cos\left(x\right)^2}$
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