$\lim_{x\to3}\left(\frac{\left(x^2-9\right)}{2x+x^2-3}\right)$
$\left(2a-\frac{1}{4}\right)\left(2a+\frac{1}{4}\right)$
$\lim_{x\to2}\left(x^2-3x+4\right)$
$4>3x+5$
$\left(x+20\right)\left(x-20\right)+400$
$\frac{\sin^2\left(2x\right)}{\left(1+\cos\left(2x\right)\right)^2}=\sec^2\left(x\right)-1$
$\frac{dy}{dx}=x^5$
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