$2x+12+8x+6+5x$

$6mn^3+4m^3n-7m^5n^5,si\:m=-2\:y\:n=-1$

$\left(tanx+1\right)\left(\sqrt{3}tanx-1\right)=0$

$\left(3-25\right)\cdot\left(-1\right)$

$\left(2s^2-5t\right)\left(2z^2+t\right)$

$\tan\left(x\right)\cos\left(x\right)=\frac{1}{2}$

$\frac{\left(10n^2-22mn+12m^2\right)}{2m-2n}$