$\frac{dy}{dx}=\left(y^2+1\right)^{-1}$

$\left(\frac{1}{5}z^4-\frac{5}{3}z^3\right)^2$

$0.000\:+\:9.0126+14+145.147+12$

$-6\left(\frac{2}{0.8}\pi\:\left(0.5-0.2\right)\right)+15$

$\left(1-cos\:0\right)\left(1+cos\:0\right)=sin^2\:0$

$\frac{dy}{dx}=\frac{1+x+y+xy}{1-x+y-xy}$

$3^2+2ab+b^2$