$8^5\cdot8^3$
$\int\left(\left(4x+1\right)\left(2x^2+x-3\right)^4\right)dx$
$\tan^2x+5=\sec^2x+4$
$\int-\frac{6}{\sqrt{-x^2+36}}dx$
$\int x^3\sqrt{-x^2+16}dx$
$6\csc x+7=0$
$45+9n+6$
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