Final answer to the problem
$\frac{3}{4}x\cos\left(x\right)^2\sin\left(x\right)-\sqrt{18}\sqrt{x}\sqrt{\sin\left(x\right)}+13=x-\frac{3}{4}\sin\left(x\right)^3$
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Step-by-step Solution
How should I solve this problem?
- Find the derivative using the product rule
- Find the derivative using the definition
- Find the derivative using the quotient rule
- Find the derivative using logarithmic differentiation
- Find the derivative
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Load more...
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1
Simplifying
$\frac{3}{4}x\cos\left(x\right)^2\sin\left(x\right)-\sqrt{18x\sin\left(x\right)}+13=x-\frac{3}{4}\sin\left(x\right)^3$
2
The power of a product is equal to the product of it's factors raised to the same power
$\frac{3}{4}x\cos\left(x\right)^2\sin\left(x\right)-\sqrt{18}\sqrt{x}\sqrt{\sin\left(x\right)}+13=x-\frac{3}{4}\sin\left(x\right)^3$
Final answer to the problem
$\frac{3}{4}x\cos\left(x\right)^2\sin\left(x\right)-\sqrt{18}\sqrt{x}\sqrt{\sin\left(x\right)}+13=x-\frac{3}{4}\sin\left(x\right)^3$
