$2\:+\:cos\:2x=\:3\:cosx$
$\frac{dy}{dx}=\frac{\left(1-x\right)}{y^{16}x}$
$y^2=6-y^2$
$x^3\cdot\frac{1}{x}^4$
$\tan x\left(1-\cot^2x\right)$
$\:\:\:-\:8a\:+\:7x\:-\:3m\:\:\:\:\:\:\:\:\:3a\:-\:8m\:-\:5x\:\:$
$-x^2+13x+12$
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