$( x + 8 ) ( x - 3 )$
$4x^4+1=0$
$\lim_{x\to0}\left(\frac{5e^{x-5}}{x}\right)$
$\int_{-\infty}^5\left(\frac{1}{x^2+1}\right)dx$
$\int\frac{3y^3+13y+4}{y^3+4y}dy$
$\int\frac{secx}{secx+tanx}dx$
$40\cdot2$
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