$\left(b^3+8c\right)\left(b^3+8c\right)$
$\frac{15}{s\left(s^2+4\right)}$
$\lim_{x\to-1}\left(\frac{x^3+3x^2+3x+1}{x^2-1}\right)$
$-4\cdot5+6+5^2$
$8x^2-12x-8$
$-27c^2+9c$
$\log\left(x^3\right)+2\log\left(x^8\right)-3\log\left(x^3\right)$
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