$\int6sec^3\left(x\right)dx$
$\frac{dy}{dx}=\frac{x^2+4}{y^2-5};\:y\left(0\right)=1$
$-7x=42$
$12x^5+14x^4-10x^3$
$\left(44-s\right)^2$
$\frac{z^2}{2-z^2}$
$a^5bc3+\frac{3}{4}a^6bc3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!