$8x\:<\:40$
$\left(\cos\:\left(20t\right)\right)^2$
$\int\frac{1}{\left(x-1\right)\left(x^2-16\right)}dx$
$\left(5a^3-3b^2\right)^3$
$xy'-xy=4y$
$-24.37+5.1$
$\int\sin\left(t\right)\ln\left(\cos\left(t\right)\right)dt$
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