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$\frac{36\left(x^2-1\right)}{\left(x^2+3\right)^3}=0$

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Other solved exercises

$6b+7b-10$

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$\sqrt[3]{a^6}$

$2\left(5x-4y\right)-\left(7x+y\right)\:$

$-\frac{v}{9}=-35$

$\sqrt{-15}$
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