$y'=\:\left(\frac{1-x-y}{x+y}\right)$
$\lim_{x\to-1}\left(2x\right)$
$\left(\frac{35a^9b^3}{21a^7b^5}\right)^4$
$y=\frac{x^2+2x}{x^3}$
$3x-1\le2x+2$
$y^2=36x$
$\int_0^{x^4}\left(\sqrt{u}\right)du$
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