$12x\:-\:4\left(2+3x\right)$
$\lim_{x\to-1}\left(\frac{2x^2-2}{x+1}\right)$
$+1500-70+100-300$
$\frac{d}{dx}19x-12$
$6+\ln\left(x+3\right)=8$
$\int\frac{4x^2+2x-1}{x^2\left(x+1\right)}dx$
$g\left(4\right)=\:\frac{3}{4}x^{-1}-\frac{1}{2}\sqrt{x}$
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