$\frac{6x^4-16x^3+34x^2-2x+16}{x^2+4}$
$\frac{6}{2+4x}$
$\frac{\left(2x+2\right)}{\left(-x+2\right)}=4$
$3\cos^2\left(x\right)-\cos\left(x\right)=0$
$\left(x-y\right)\cdot x=y+x$
$\frac{1-cot^2\theta\:}{1+cot^2\theta\:}+1=2sin^2\theta\:$
$-x=67$
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