$x\cos^2\left(y\right)dx=\tan\left(y\right)dy$
$3\cos\left(x\right)-\cos\left(2x\right)=2$
$6\cdot\:\left(3\right)^2-\left(14\right)\left(3\right)+2$
$\frac{\left(x^3+2x^2\right)}{3x^2-1}$
$w^{-1}$
$\left(2x+10\right)\left(2x-5\right)$
$\int\frac{7}{x^2-6x}dx$
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