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Find the roots of $x^2+6x+8=20$

Step-by-step Solution

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Solution

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Final answer to the problem

$x=\frac{-6+\sqrt{84}}{2},\:x=\frac{-6-\sqrt{84}}{2}$
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Step-by-step Solution

How should I solve this problem?

  • Find the roots
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find break even points
  • Load more...
Can't find a method? Tell us so we can add it.
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Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$x^2+6x=20-8$

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$x^2+6x=20-8$

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Learn how to solve equations problems step by step online. Find the roots of x^2+6x+8=20. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Subtract the values 20 and -8. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=6 and c=-12. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

Final answer to the problem

$x=\frac{-6+\sqrt{84}}{2},\:x=\frac{-6-\sqrt{84}}{2}$

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Function Plot

Plotting: $x^2+6x+8-20$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\log_3\left(81\right)=4$

Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

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