$y^8-16y^6$
$x^2dx+4ydy=0$
$m^2+12^2$
$\frac{dy}{dx}-y\cdot cotg\left(x\right)=0$
$y'=\frac{y+1}{x-1}$
$\left(x-\frac{2}{7}\right)^3$
$\frac{dy}{dx}\left(6+x^4\right)=\frac{x^3}{y}$
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