$\frac{x^2y}{6}-\frac{5x^3y}{6}+\frac{3x^4y^3}{2}$
$\frac{d}{dx}\left(xy-1\text{x}^2\:=\:9\right)$
$f\left(x\right)=xy-xy^2$
$5xy-1=0$
$\left(5x^2\:y^3\:z\right)^2$
$3\:x\:\left(x^2-3x\right)+5x$
$3\left(x-1\right)-2\left(x-1\right)-6<2x$
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