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Solve the quadratic equation $x^2+x+1=113$

Step-by-step Solution

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Solution

Final answer to the problem

$x=\frac{-1+\sqrt{449}}{2},\:x=\frac{-1-\sqrt{449}}{2}$
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Step-by-step Solution

How should I solve this problem?

  • Find the integral
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Find break even points
  • Load more...
Can't find a method? Tell us so we can add it.
1

Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$x^2+x=113-1$

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$x^2+x=113-1$

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Learn how to solve problems step by step online. Solve the quadratic equation x^2+x+1=113. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Subtract the values 113 and -1. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=1 and c=-112. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

Final answer to the problem

$x=\frac{-1+\sqrt{449}}{2},\:x=\frac{-1-\sqrt{449}}{2}$

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Function Plot

Plotting: $x^2+x+1-113$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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