$\frac{8^8}{8^3}$
$\frac{1-\tan\left(x\right)}{\csc\left(x\right)-\sec\left(x\right)}=\sin\left(x\right)$
$-10x+-5=-15$
$16m^6\:x^4+40m^3\:x^2\:n^2+25n^4$
$dx=x^{\text{4}}ydy$
$6b^6+21b^3$
$x^2y^2\frac{1}{2}xy+\frac{1}{16}$
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