$-2x>6$
$4k-2=-90$
$cos2a+6cos^2a=1$
$\frac{d}{dx}x^2+4xy+y^2=13$
$\frac{\tan\left(a\right)}{1+\sec\left(a\right)}+\frac{1+\sec\left(a\right)}{\tan\left(a\right)}$
$\left(4-2x\right)^2$
$3y^2-15y+18$
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