$3\left(x+1\right)^2-4$
$y'=2xe^{x^2}-2xy$
$0,6^{\infty}$
$2+2\:-3\:x\:4\:+9$
$\frac{\left(e^{\frac{x}{3}}-1-\frac{x}{3}-\frac{x^2}{18}\right)}{x^3}$
$2\left(2a\right)\left(-b\right)$
$y'=\left(x+y\right)^2+x+y$
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