$\left(-2^2-1^2\right)$
$3x^2+5x-6;x=-5$
$5^2+30$
$\lim_{x\to-\infty}\left(\frac{\ln\left(x^4+\right)}{x}\right)$
$\int_1^e\left(\frac{2x^2-5}{x}\right)dx$
$\frac{\left(4x^2+5\right)^2}{\left(x+1\right)^2\left(7x+2\right)}$
$\lim_{t\to\frac{1}{2}}\left(\frac{\:6t-1}{t}\right)$
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