$\frac{dy}{dx}=ax^2$

$\left(x+2\right)\left(2x+5\right)$

$x^2-14x+49x^2$

$\lim_{x\to\infty}\left(\frac{\ln\left(3+2e^x\right)}{x}\right)$

$\:\left(\:-14c^4-8z^6\right)\:\left(\:-14c^9+3z\right)$

$44\:=\:6\:\left(1+4c\right)\:-5c$

$13\sec\left(x\right)+6=12\sec\left(x\right)+8$