$\frac{\left(-1\right)^2+\left(-1\right)-2}{\left(-1\right)+2}$
$\left(4a-3b\right)\left(7a-8b\right)$
$\cos^2\left(4x\right)+\cos^2\left(4x\right)$
$16x+5<8x$
$24\:-\:\left(-10\right)\:+\:\left(-6\right)$
$v^2\frac{dv}{dx}=\left(2+x\right)^3$
$-24x^7-36x^5+24x^4+12x^3$
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