$\frac{b}{6}=3$
$8b^3\:+512$
$\left(3x+6\right)^3$
$4\sqrt{50}$
$\lim_{x\to36}\left(\frac{1}{\left(\sqrt{x}-6\right)}-\frac{12}{x-6}\right)$
$\left(a^8+16\right)^4$
$\lim_{x\to2}\left(\frac{4x-3}{x^2-4x+4}\right)$
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