$5x^2+6x+1=0$
$6xy-18ax$
$\frac{dy}{dx}=e^{4x}y^2+e^{4x}$
$x^2-8x+16=289$
$-5d^6\left(8d^6\right)$
$\left(-6\right)\left(-5\right)\left(-3\right)\left(4\right)\left(-3\right)\left(-5\right)$
$\left(6x-4y\right)^3$
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