$\frac{dx}{dt}=-x+1$
$\frac{2}{5}x+4\le-12$
$\int\left(x^2-5\right)^32xdx$
$7\left(1^3\right)^6\left(5\right)^1$
$\int x^4\left(36-x\right)^{\frac{5}{2}}dx$
$4f^2-9a^2$
$\sqrt{5\cdot6-1}$
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