$\frac{z^3}{\left(z-1\right)^2\left(z+1\right)}$
$b^6+64c^6$
$\frac{dy}{dx}=\left(x^3-2\right)\left(3x^2\right)$
$\frac{x^4-3x+2}{x-3}$
$\left(\frac{-2d^{11}f^6}{c^{18}}\right)^2$
$15ab-3b-5a+1$
$8cos5xsec3x$
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