$-1^{-5}$
$\left(-6x^2\right)\left(3x+4\right)$
$cos\left(t\right)-cos^{\left(3\right)}\left(t\right)=cos\left(t\right)sin^{\left(2\right)}\left(t\right)$
$xarccos2x-\frac{\sqrt{1-4x^2}}{2}$
$\int2bx^2dx$
$6-\left(-6\right)\cdot\left(-8\right)$
$\left(ax+2\right)^3$
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