$x^2=\left(4x^2y^3\:+1\right)^2$
$\left(-1\right)\cdot34$
$\lim_{x\to3}\left(\frac{\sqrt{x-1}-2}{x-3}\right)$
$\left(6x^2-9\right)\left(6x^2+1\right)$
$10x+-90x+1$
$x^2-4x-3>0$
$m^3+10m^2+2m-13$
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