$\frac{18b^2+8a^2\:\:}{4a^2+9b^2}\:$
$8c-4-2c+5$
$\lim_{x\to0}\left(\frac{x^2-4x+5}{x^3-x-1}\right)$
$\frac{x^{4}}{x^{4}y^{-2}y^{4}}$
$-11\:x\:7$
$y\left(8y\right)$
$x2\:-10\:x\:+25$
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