$\left(x-3\right)\left(x^2-9\right)\left(x+3\right)$
$64x^4-36y^8$
$\int5x^3\:dx$
$\left(\frac{1}{2}-3m\right)^2$
$5x+3\le2$
$\int\frac{\left(1+\tan\left(x\right)\right)^2}{tanx}dx$
$-14+25+6+78-28-6-83+14+16+87$
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